An electric iron draws a current of 4 Ampere on a 240 V supply
1.what is its power
2.what is its resistance
3.what is the cost of using the iron for the month of January 10 hours a day if 1 KWH costs Rs.3.40?
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power =240×4=960
resistance =240/4=60
total consumption =10×1×31=310unit
cost of 1 unit =3.4
cost of 310 unit =310×3.4=1054
resistance =240/4=60
total consumption =10×1×31=310unit
cost of 1 unit =3.4
cost of 310 unit =310×3.4=1054
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