Question

find the value of the following

Answer 1

Given Equation is 3x - 4y = 0 ---- (1)

Given Equation is xy = 12 ----(2)

On cubing (1) on both sides, we get

= > (3x - 4y)^3 = 0

We know that a^3 - b^3 = a^3 - b^3 - 3ab(a - b)

= > 27x^3 - 64y^3 - 3(12)(3x - 4y) = 0

= > 27x^3 - 64y^3 - 36(0) = 0

= > 27x^3 - 64y^3 = 0

Hope this helps!