Math, asked by bhavin007, 16 days ago

An electric iron has rating of 450W ,220v it is used 5 hour daily calculate current flowing through it and resistance when in use. And energy consumed in KWH per day.

Answers

Answered by Pohleen
0

Answer:

Energy of one day =Power×Time=400W×8h=3.2KWh

Energy of 30 days =3.2KWh×30=96KWh

So, cost of the energy =96×3=Rs.288

Answered by piyushsahusahu000
0

An electric iron rated 450 W operates 5hour/day.

Energy in one day=pawer×time

=450×5

=2250

2.25 KWH

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