An electric iron of 1200w is used for 30 min every day.find electric energy consumed in month of april
Answers
Answered by
11
Power = enegy/ time
time = 0.5 hour
hence, total time in month of april
= 0.5* 30
= 15 hr.
power = energy/ time
1200W = x / 15
x = 1200*15
x = 18000
x= 18kwh
Hence the enegy consumed in the month of april is 18kwh.
time = 0.5 hour
hence, total time in month of april
= 0.5* 30
= 15 hr.
power = energy/ time
1200W = x / 15
x = 1200*15
x = 18000
x= 18kwh
Hence the enegy consumed in the month of april is 18kwh.
Answered by
0
Answer:
It is given that,
Power =1200W=1.2kWh
Time = 30 min / day × 30 days =0.5h×30= 15 h
Energy =Power×Time=1.2×15= 18kWh.
Hope it helps!
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