Question

An electric iron of resistance 20 A2 takes a current of 5 A. Calculate the
heat developed in 30 s.​

Answer 1

Answer:-

• Resistance=R=20ohm
• Current=I=5A
• Time=t=30s=0.008Hour
• Heat=H=?

We know that

$\boxed{\sf H=I^2Rt}$

$\\ \tt\longmapsto 5^2\times 20\times 0.008$

$\\ \tt\longmapsto 25\times 20\times 0.008$

$\\ \tt\longmapsto 500\times 0.008$

$\\ \tt\longmapsto Heat=4J$