find the zeros of 6 x square - 3 - 7x also with the relationship between the zeros and Coefficient according to class 10
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Answer:
(-1/3), 3/2
Step-by-step explanation:
6x²-3-7x=0
6x²-7x-3=0
6x²-9x+2x-3=0
(6x²-9x)+(2x-3)=0
3x(2x-3)+1(2x-3)=0
(3x+1)(2x-3)=0
(3x+1=0)(2x-3=0)
x=(-1/3), x=3/2
Therefore, the zeros of 6x²-3-7x are -1/3 and 3/2.
Sum of zeros = (-1/3)+3/2 = (-2)+9/6 = 7/6 = (-7)/6 = -(Coefficient of x)/Coefficient of x²
Product of zeroes = (-1/3)×3/2 = (-3/6) = Constant term/Coefficient of x²
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