Question

an electric iron of resistance 20 ohm takes a current of 5 A calculate the heat developed in 30 seconds ​

Answer 1

Answer:

R) = 20 Ω

(I)= 5 A

(t)= 30 s

Now we know that H= I2Rt

                        use it here     = 5×5×20×30

                               = 15000J=1.5×104J

The heat developed in 30s is 1.5×104J

Answer 2

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please refer to the attachment