Question

An electric iron of resistance 20om takes a current of 5 A. Calculate the heat developed in
30 s.

please tell correct​

Answer 1

(R) = 20 Ω

(I)= 5 A

(t)= 30 s

Now we know that H= I2Rt

                        use it here     = 5×5×20×30

                               = 15000J=1.5×104J

The heat developed in 30s is 1.5×104J.

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Answer 2

Explanation:

H=I²Rt

H= 5²*20*30

H= 25*600

H= 15000j

H= 1.5*10⁴j