Question

Solubility of ba so4 in pure water is 4*10^-5 m . Solubiity of baso4 in 0.01m bacl2 solution will be:

Answer 1

Answer:

Solubility of BaSO₄ in solution (s) is

s = 0.004 mol/ L

s = 4 X 10⁻³ mol/ L

Explanation:

Given

Solubility of BaSO₄ (ksp) = 4 X 10⁻⁵ M

Molarity of BaCl₂ solution = 0.01 M

Solubility of BaSO₄ in solution (s) = ??

Solution

Dissociation of BaSO₄  can be written as

          BaSO₄ ---------> Ba²⁺ + SO₄²⁻

According to ICE table

          BaSO₄ ---------> Ba²⁺ + SO₄²⁻

          I                       0.01 M    0

         C                        +s         +s

         E                      s + 0.01    s

therefore we can write

ksp = ( s + 0.01) . s

as the value of ksp is very small as compared to silver ions initial concentration

we can use approximation

s + 0.01 ≈ 0.01

Ksp = 0.01 . s

s = 4 X 10⁻⁵ / 0.01

s = 0.004 mol/ L

s = 4 X 10⁻³ mol/ L