An electric iron rated as 750W and 220V has an electric fuse of rating 2A. What is expected from such an electric iron.
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Answer:
Given:
P= 750W
V= 220v
We know,
P=VI
750= 220*I
750/220= I
I= 3.4A
Since, the current drawn by the electric iron is higher than the fuse rating, The fuse wire will break.
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