Question

An electric kettle can hear certain quantity of water from 19°C to 100°C in 6 min, time taken to boil the same quantity of water into steam ar 100 defrwe celcius is ( L of steam is 540 calories ler grams )

Answer 1

An electric kettle can hear certain quantity of water from 19°C to 100°C in 6mins. The time taken to boil the same quantity of water into steam is 40 mins.

1) the power generated by kettle is Q/t

2) Q = m S dT = 4.2 * (100-19) = 340.2 KJ/kg

3) So the power generated is 340.2 / 360 = 0.945 Kwatts

4) this power is utilized to change it to steam.

5) So the time required = m* L/ power

6) time t = (540 * 4.2) / 0.945 = 6 mins.

Answer 2

answer is 40 minutes hope it helps you