Question

An electric kettle connected to the 230 V mains supply draws a current of 10 A. Calculate:; (a) the power of the kettle.; (b) the energy transferred in 1 minute.

Answer 1

Answer :-

(a) 2300 j

(b) 138000 j

---------------------------

Explanation :-

Given :-

• V = 230

• I = 10
• T = 1 min = 60 sec

To Find :-

• ( a ) Power of kettle
• ( b ) Energy transferred in 1 min

Solution :-

we know that,

P = VI

So,

( a ) P = 230 X 10

P = 2300 J

----------------------

( b ) we know that energy = P X T

T = 1 min = 60 sec

So,

E = 2300 X 60

E = 138000 J

Answer 2

» An electric kettle connected to the 230 V mains supply draws a current of 10 A.

Here ..

• Voltage (V) = 230 V

• Current (I) = 10A

_______________ [ GIVEN ]

• We have to find a) Power (P) of kettle

b) Energy (E) transferred in 1 minute.

______________________________

a)

We know that

Power = Voltage × Current

P = VI

Put the known values in above formula

→ P = 230 × 10

→ P = 2300 W (watt)

_____________________________

$\huge{\bold{P\:=\:2300\:W}}$

(Power of the kettle)

_____________ [ ANSWER ]

_____________________________

b)

We know that

Energy = Power × Time

E = P × T

Given : Time = 1 min

1 min = 60 sec

Time = 60 sec

Now, put the known values in above formula

→ E = 2300 × 60

→ E = 138000 J (joule)

______________________________

$\huge{\bold{E\:=\:138000\:J}}$

(Energy transferred in 1 min)

______________ [ ANSWER ]

_____________________________