an electric kettle is rated 2.5kW , 2.50V. What should be the current capacity of the wire with it??
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Answered by
11
Power=2.5kw=2500w
Voltage=2.5v
Current=p/v=2500/2.5=1000amphere
Answered by
3
Here I=1000A as there is a formula where P=VI firstly converting the KW into W we get 2500 and then putting in the formula 2500=2.5×I
from which we get the value of I =2500/2.5
from which we get the value of I =2500/2.5
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