an electric kettle is rated 500 Watt of 220 volt. it is used to heat for hundred gram of water for 30 seconds as using the voltage to of 220 volt. calculate the rise in temperature of water . specific heat capacity of water is equal to 4200 joule per degree Celsius.
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power of kettle p=500w
working v=200v
heat develop in 30s
h=pt, 500*30=15000j
let delta t be rise in temperature: of water
therefore,
h=m*s*delta t
15000=0.4*4200*delta t
delta t=8.93 degree centigrade
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