Question

an electric kettle is rated 500 Watt of 220 volt. it is used to heat for hundred gram of water for 30 seconds as using the voltage to of 220 volt. calculate the rise in temperature of water . specific heat capacity of water is equal to 4200 joule per degree Celsius.​

Answer 1

Answer:

power of kettle p=500w

working v=200v

heat develop in 30s

h=pt, 500*30=15000j

let delta t be rise in temperature: of water

therefore,

h=m*s*delta t

15000=0.4*4200*delta t

delta t=8.93 degree centigrade