Question

an electric kettle is rated at 230v, 1000 watt. what is the resistance of its element? what is the maximum current that can pass through its element

Answer 1

Hii friend,

Given,

V(potential difference)= 230volts

P (power)= 1000W

To find:-

(1) Resistance
(2) current

We know the formula,

P= V²/R

Then,

R= V²/P

R= 230×230/1000

R= 52.9 ohms...............(1)

To find Current:-

Then by ohms law,

V=IR

I=V/R

I= 230/52.9

I=4.34 A(ampere).

Hope this helps you a little!!!!

Answer 2

Answer:

Explanation:firstly use the formula P=V^2/R

R=V^2/PR then solve

R=230.230/1000

R=52.9Ohm

then find safe current ,it means we have to find current (I)

I=V/R

I=230/52.9=4.35A