Question

An electric kettle is rated at 25 W. Calculate: (a) the quantity of heat generated in 2 s; (b) the rise in temperature of 150 g of water if the electric kettle is switched on for 5 minutes and the specific heat capacity of water is 4 J g-1°C-1 .

Answer 1

Answer:

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Explanation:

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 J

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o C= specific heat of water and boiling point temp=100

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o C= specific heat of water and boiling point temp=100 o

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o C= specific heat of water and boiling point temp=100 o C

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o C= specific heat of water and boiling point temp=100 o CHeat lost =14.25×10

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o C= specific heat of water and boiling point temp=100 o CHeat lost =14.25×10 5

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o C= specific heat of water and boiling point temp=100 o CHeat lost =14.25×10 5 −10.71×10

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o C= specific heat of water and boiling point temp=100 o CHeat lost =14.25×10 5 −10.71×10 5

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o C= specific heat of water and boiling point temp=100 o CHeat lost =14.25×10 5 −10.71×10 5 =3.54×10

Energy consumed by electric kettle in 9.5 min =Pt=(2.5×10 3 )×(9.5×60)=14.25×10 5 JEnergy usefully consumed =msΔT=3×(4.2×10 3 )×(100−15)=10.71×10 5 where s=4.2J/g o C= specific heat of water and boiling point temp=100 o CHeat lost =14.25×10 5 −10.71×10 5 =3.54×10 5