An electric kettle of resistance 20ohm takes current of 5A. calculate the heat developed in 30 seonds.
ajoychetry44167:
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Answers
Answered by
1
Given ,
I = 5A
R = 20 ohm
time = 30 sec
since we know
Heat (H) = I^2 R T
= 5^2 × 20 × 30
= 15000 J
I = 5A
R = 20 ohm
time = 30 sec
since we know
Heat (H) = I^2 R T
= 5^2 × 20 × 30
= 15000 J
Answered by
0
Answer:
Given, resistance ( R) = 20ohm
current (I) = 5A
time(T) = 30s
H = I² × R × T
=> H = 5² × 20 × 30
=> H = 25 × 600
=> H = 15000 joules
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