Question

An electric lamp connected in series with a capacitor and an ac source is glowing with a certain brightness.how does the brightness of the lamp changes on reducing the1. capacitance and frequency

Answer 1

Answer:

On decreasing the capacitance and frequency the brightness of the bulb will decrease

Explanation:

As we know that net impedence of the circuit when capacitor and resistor is connected to AC source is given as

$z = \sqrt{R^2 + (\frac{1}{\omega C})^2}$

now the current in the circuit is given as

$i = \frac{V}{z}$

now in order to increase the brightness the current must be increased and vice versa

so here when Capacitance of the capacitor is decreased then the impedence of the circuit will increase and hence the current will decrease

So the brightness of the lamp will decrease

Also if the frequency of the source is decreased then the impedence of the circuit will increase and hence the current will decrease, so the brightness of the lamp again decreases.

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Topic : Impedence of RC circuit

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