Question

An electric lamp of 100 Ω, a toaster of resistance. 50 Ω , and a water filter of resistance 500 Ω are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all the three appliances, and what is the current through it?

Answer 1

Resistance of electric lamp,toaster & water filter=100 ohm, 50 ohm & 500 ohm Respectively

               Potential difference = 220 volt        Total resistance of the three appliances in parallel = 1/R = 1/R1 + 1/R2 + 1/R3        = 1/100 + 1/50 + 1/500        1/R = 5 + 10 + 1/500        1/R = 16/500 = 4/125        = 125/4 = 31.25 ohm        V = I × R        220 = I × 31.25        I = 7.04 amp        Hence current through the electric iron = 7.04 amp.

Answer 2

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