An electric lamp of 100 Ω, a toaster of resistance 50 Ω, and a water filter of resistance 500 Ω are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances, and what is the current through it ?
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(1) Total resistance (R) can be calculated as shown below.
=》1/R = 1/R₁ + 1/R₂ + 1/R₃
=》1/R = 1/100 + 1/50 + 1/500
=》1/R = ( 5 + 10 + 1 )/500
=》1/R = 16/500
=》500/16 = R
=》Total Resistance (R) = 500/16 Ω
=》R = 31.25 Ω
(2) According to ohm’s law the current through a conductor between two points is directly proportional to the voltage across the two points.
=》V ∝ I or V = IR
=》R is constant called resistance.
=》R = V/I
=》500/16 = 220/I
=》I = 220 × (16/500)
=》I = 7.04 A
Therefore, the resistance of the electric iron is31.25 Ω and the current flowing through it is 7.04 A.
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