Question

An electric lamp, whose resistance is 20 12, and a conductor of 40
resistance are connected to a 6 V battery (Fig. 12.9). Calculate (a) the
total resistance of the circuit, (b) the current through the circuit, and
(c) the potential difference across the electric lamp and conductor​

Answer 1

Explanation:

ANSWER

a). the total resistance of the circuit =20Ω+4Ω=24Ω

b). The current through the circuit= current through the bulb= current through the conductor.

The current through the circuit=

the voltage of the battery

voltage applied

.

the current through the circuit =

24

6

amp

The current through the circuit = 0.25amp

c). The potential difference across the lamp and the conductor.

(i) The potential difference across the electrical lamp =0.25×20=5volt

(ii) The potential difference conductor =0.25×4=1 volt

d). Power can be calculated as

current through the lamp

voltage across the lamp

power=

0.25

5

→20W.