Question

An electric lamp, whose resistance is 20 A, and a conductor of 4 0
resistance are connected to a 6 V battery (Fig. 12.9). Calculate (a) the
total resistance of the circuit, (b) the current through the circuit, and
(c) the potential difference across the electric lamp and conductor.​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Explanation:

A). the total resistance of the circuit =20Ω+4Ω=24ω

B). The current through the circuit= current through the bulb= current through the conductor.

The current through the circuit=  

the voltage of the battery

voltage applied

​  

.

the current through the circuit =  

24

6

​  

amp

The current through the circuit = 0.25amp

C). The potential difference across the lamp and the conductor.

The potential difference across the electrical lamp =0.25×20=5volt

The potential difference conductor =0.25×4=1 volt

D).  Power can be calculated as  

current through the lamp

voltage across the lamp

​  

 

    power=  

0.25

5

​  

→20W.