An electric lamp whose resistance is 20 Ω and a conductor of 4 Ω resistance
are connected in series to a 6V battery. Find the current through the circuit and
the potential difference across the electrical lamp and conductor.
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An electric lamp, whose resistance is 20 Ω, and a conductor of 4 Ω resistance are connected to a 6 V battery. ... V1 = IR1 = 0.25 A x 20 Ω = 5 V. Potential difference across the conductor is, V2 = IR2 = 0.25 A x 4 Ω = 1 V.
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Electricity. An electric lamp, whose resistance is 20 Ω, and a conductor of 4 Ω resistance are connected to a 6 V battery. Calculate (a) the total resistance of the circuit, (b) the current through the circuit, and (c) the potential difference across the electric lamp and conductor. = 24 Ω
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