Question

An electric lamp, whose resistance is 20Ω, and conductor of 4Ωresistance are connected to a 6V battery. Calculate. ...............
(a) The total resistance of the circuit.
(b) The current through the circuit.
(c) The potential difference across the electric lamp and conductor.

Answer 1

A.    The total resistance of the circuit = 20Ω + 4Ω =24 Ω

 

B.     The current through the circuit = current through the bulb = current through the conductor

The current through the circuit = Voltage applied/ the voltage of the battery

The current through the circuit = (6/24) amp

The current through the circuit =0.25 amp

 

C.     The potential difference across the electric lamp and the conductor.

The potential difference across the electric lamp = 0.25 ×20 = 5 volt

The potential difference across the conductor = 0.25 × 4 = 1volt