Question

An electric lamp whose resistance is 8 ohms and a conductor of 2 ohms resistance are connected in series to a 5 volt battery. Calculate

A. The total resistance of the circuit B. The current through the circuit

C. The potential difference across the electric lamp and the conductor​

Answer 1

Explanation:

resistance of lamp: 8 ohms

resistance of conductor: 2 ohms

voltage of circuit: 5 volt

A) Total resistance = 8 + 2 = 10 ohms

B) current(I) = voltage/ total current

5/10 = 1/2 = 0.5 A

C) potential difference across the lamp and conductor:

V = IR

V = 5 × 10 = 50V