Physics, asked by wwwrathna9731819273, 1 year ago

An electric motor is rated 1.5 KW - 250 we calculate (a) the current flowing into the motor (b) the energy consumed in 1 second (c) that time in which it will consume 90 kwh of energy

Answers

Answered by rahul123437
7

(a)Current = 6 Amp.(b) Energy consumed in 1 second = 1500 joules. (c) That time =60sec.

Given:

Electric power = 1.5KW = 1500 W    voltage = 250 v

To find:

(a) The current flowing into the motor.

(b) The energy consumed in 1 second.

(c) That time in which it will consume 90 kwh of energy.

Formula used:

Electric power = voltage × current

Explanation:

(a) The current flowing into the motor.

Electric power = voltage × current

              1500  = 250 × current

           Current = \frac{1500}{250} = 6 Amp.

(b) The energy consumed in 1 second.

Electric power = 1500 W = 1500 Joules per second.

So the energy consumed in 1 second = 1500 Joules.

(c) That time in which it will consume 90 kwh of energy.

Energy consumption = 90 kwh =\frac{90}{1} = 90 KW.

So that time = \frac{Electric\ power}{Energy\ consumption} = \frac{90}{1.5} = 60 sec.

To learn more....

1)A small town with a demand of 800 kW of electric power at 220 V is situated 15 km away from an electric plant generating power at 440 V. The resistance of the two wire line carrying power is 0.5 W per km. The town gets power from the line through a 4000-220 V step-down transformer at a sub-station in the town. (a) Estimate the line power loss in the form of heat. (b) How much power must the plant supply, assuming there is negligible power loss due to leakage? (c) Characterise the step up transformer at the plant.

https://brainly.in/question/11372016

2)One thousand watts of electric power are transmitted to a device by means of two wires, each of which has a resistance of 2 ohms. If the resulting potential difference across the device is 100 volts, the potential difference across the source supplying the power is: A. 20 V B. 40 V C. 100 V D. 140 V E. 500 V.

https://brainly.in/question/6373446

     

Answered by adventureisland
1

Explanation:

(a)Current is 6 Amp.

(b) Energy used in 1 second is 1500 joules.

(c) time is 60sec.

Electric power is 1.5KW i.e., 1500 W    

voltage = 250 v

We have to find:

(a) The current flowing into the engine.

(b) The power used in 1 second.

(c) time in which it will use 90 kWh of electricity.

Formula

Electric power = VxI

(a) The current flowing into the engine.

 1500  = 250 × current

I = 6 Amp.

(b) The energy used in 1 second.

Electric power = 1500 W .

Therefore, energy used in 1 second = 1500 Joules.

(c) Time in which it will use 90 kWh of energy.

Energy used = 90 kwh

Therefore, Time = 60 second

To learn more:

i)An electric motor of power 200 w is switched on for 1 minute and 40 ...

https://brainly.in/question/6771489

ii)An electric motor raises a load of 0.2 kg, at a constant speed ...

https://brainly.in/question/13410788

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