an electric motor of power 6 kW is used for 2 min .Find the energy supplied by the motor.
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Answer:
7,20,000 Joule or 720 kilo-Joule or 720 kJ
Explanation:
Power = 6 kW
Time = 2 min = 2/60 hours = 1/30 hours
Energy (kWh) = 6 * 1/30 = 1/5 = 0.2 kWh
∵ Since, One kilowatt-hour (kWh) is equivalent to the energy of 1,000 joules used for 3,600 seconds
Energy (in Joule) = 0.2 * 1000 * 3600
= 7,20,000 or 720 kJ or 0.72 MJ
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