Question

An electric oven of 1.5 KW is operated in a domestic circuit (220 V) that has a current rating of 5 A
What result do you expect in this case? Explain.
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Answer 1

Answer:

6.818 A

Explanation:

Current drawn by the electric oven can be obtained by the expression,

P = VI

I= P/V

Where,

Current = I

Power of the oven, P = 1.5 kW = 1500 W

Voltage supplied, V = 220 V

I = 1500 / 220

I = 6.818 A

Hence, the current drawn by the electric oven is 6.818 A, which exceeds the safe limit of the circuit. Fuse element of the electric fuse will melt and break the circuit.

Answer 2

Explanation:

Current drawn by the electric oven can be obtained by the expression,

P = VI

Where,

Current = I

Power of the oven, P = 2 kW = 2000 W

Voltage supplied, V = 220 V

I = 2000/220 V = 9.09 A

Hence, the current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit. Fuse element of the electric fuse will melt and break the circuit.