find the four angles of a cyclic quardilateral ABCD in which angleA=(2x-3)°, angleB=(y+7)°,angleC=(2y+17)° and angleD= (4x-9)°.
PLZ EXPLAIN STEP BY STEP
A=63°
B=57°
C=117°
D=123°
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therefore x=33 and y=50
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zilch
i could not understand that
zilch-nthg
oh
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due to some personal stuffs
can u share tose stuffs ?
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