An electric pole, 16 metres high,casts a shadow of 12 metres Find the height of a
tree that casts a shadow of 18 metres under
similar conditions.
Answers
Answer:
when the lenth of the shadow is 12 meter ,then hight of the pole=16 meter
so when length shadow 1 m then hight of the pole =(16/12)m
Therefore when length of a shadow of a tree is 18 meter then hight of the tree=(16/12)★18=24 meter.
Given :
- 16 meter high pole costs a shadow of 12 m.
We Need To Find :
- Height of tree that casts a shadow of 18 m.
Step-by-step explanation :
Let height of tree be x m.
Thus, our table look like,
________________________________
| Height of object (in metre ) = 16 | x | ________________________________
| Length of shadow (in metre) = 12 | 18 |
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
Now, as the height of object increases.
The length of its shadow also increases.
∴ They are in direct proportion :
➮ 16/12 = x/18
➮ 16/12 × 18 = x
➮ 16/4 × 6 = x
➮ 16/2 × 3 = x
➮ 8 × 3 = x
➮ 24 = x.
Therefore, Height of tree is 24 m.