An electric pole casts shadow of length 10 m at a particular time when a tree 8 m high casts a shadow of length 6 m. Find the hight of the pole
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Dear friend,
Actual height of the tree = 8m
Height of the tree in shadow = 6m
.°. Angular height = 8m - 6m = 2m
Height of the electric pole in shadow = 10m
Angular height = 2m
.°. Actual height of the electric pole
= 10m + 2m = 12m
Answer. 12m is the total height of the electric pole.
Hope it helps !!!
Actual height of the tree = 8m
Height of the tree in shadow = 6m
.°. Angular height = 8m - 6m = 2m
Height of the electric pole in shadow = 10m
Angular height = 2m
.°. Actual height of the electric pole
= 10m + 2m = 12m
Answer. 12m is the total height of the electric pole.
Hope it helps !!!
Answered by
3
Answer:
length of poles shadow = 10m
length of trees shadow = 6m
high of trees = 8m
high of pole = ?
cross multiple 10/6 = 8/x
10x = 8X6
= 48. = 4.8
10 1
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