Physics, asked by beau8tshrey, 1 year ago

The car has an inertia of 500 kg and is 4.5 m long. It should be able to accelerate from rest to 29 m/s at least 50 times before the spring needs winding. The spring runs the length of the car, and a full winding compresses it to half this length. In order to meet the acceleration requirement, what must the value of the spring constant be?

Answers

Answered by kvnmurty
2
Kinetic energy imparted to the car (by spring) = 1/2 m v²   (as u =0)
   KE imparted during 50 times =  50 * 1/2 m 29²  J

compression of the spring = x = 4.5 / 2  m = 2.25 m
Potential energy given out by the spring = 1/2 k x² = 1/2 k 2.25²  J
          
Law of Energy conservation:   50*1/2 * 500* 29² = 1/2  k * 2.25²
 
          k = spring constant = 4153 kN/m
     

kvnmurty: click on red heart thanks above pls
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