A vehicle moves at a speed of 40 km/h, It is stopped by applying brakes which produces a uniform acceleration of -0.6m/s2 . How much distance will the vehicle move before coming to stop?
Answers
Answered by
0
U= 40 km/h =40×5/18=100/9 m/s
a=-0.6m/s^2
V=0 m/s
S=?
Now
V^2=u^2+2 as
0=10000/81-2×0.6×s
Or
1.2×s=10000/81
S= 10000/(81×1.2)
S=10000/97.2
So s= 102.89 ms ( approximately )
sangharsh1234:
Plz mark as brilliant ans
Similar questions