Question

An electric pole is 10 m high. A steel wire is tied to top of the pole is affixed at a point on the ground to keep the pole upright, find the lenghth of the pole.

Answer 1

ABC is a triangle from that
angle C is 45 degree
angle B is 90 degree
Let AB be the height of the electric pole and AC be the length of the wire.
In rt.△ABC,
cosec 45° = AC/AB
AC = AB cosec45°
= 10√2 m
= 10 × 1.414 m
= 14.14 m
Therefore the length of the wire is 14.14 m.

Answer 2

Given :

OA = 10 m ( electric pole)

∠B = 45°

Let OA be the electric Pole and B be  the point on the ground.

Let BA = x cm

In ∆ABO

sin 45° = AO /AB (perpendicular/ hypotenuse)

1 / √ 2 = 10 / x

x = 10 √2

x = 10 × 1.414    (Given √2 = 1.414)

x = 14.14 m

Hence, length of the wire is 14.14 m.

HOPE THIS WILL HELP YOU...