Question

An electric power source supplies a constant current of 4 A for 6.5 s to a light bulb. The total energy given off in the form of light and heat is 2.99 kJ. Calculate the voltage drop across the bulb. Enter answer here

Answer 1

Answer:

V = 115V

Explanation:

Let us first calculate the total charge, which is given by below formula;

Q = I x t ;

As per given information;

Q = 4 x 6.5

Q = 26 C

Now we calculate voltage drop from below formula;

Energy = Q x V

V = Energy/Q

As per given information;

V = 2.99 x 1000 / 26

V = 115V

Answer 2

Answer:

+115 V

Explanation:

4A means charge flow of 4C per second, so gain 26C for 6.5 s.

then, the voltage will be Joul/C that 2990/26 to obtain 115 V drop across from the PWR suppliers to light bulb.