Physics, asked by Anonymous, 10 months ago

An electric pump has 2 kW power. How much water will the pump lift every minute to a height of 10 m?

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Answers

Answered by pallavisrinivas2004
3

Answer:

Power = 2kw = 2000w , 

Height H = 10m ,

Time taken t = 60 seconds.

Therefore , the pump lifts 1200 kg or 1200 l of water to a height of 10m every minute.

Answered by BrainlyRonaldo
31

\bigstar Answer \bigstar

\checkmark Given:

⇒ Power of the pump ( P ) = 2 kW

⇒ Time ( t ) = 1 minute

⇒ Height ( h ) = 10 metres

\checkmark To Find:

⇒ How much water will the pump lift every minute to a height of 10 m with a pump of Power 2 kW

\checkmark Solution:

We know that,

Power ( P ) =

\orange{\boxed{\boxed{\sf Power(P)=\dfrac{Work \ Done \ (W)}{Time \ (t)}}}}

We know that,

Work Done ( W ) =

\red{\boxed{\boxed{\sf Work \ Done \ (W)=m \times g \times h}}}

Generally,

⇒ g = 10 m/s²

Given that,

⇒ h = 10 m

Therefore,

\blue{\sf \implies Work \ Done \ (W) = m \times 10 \times 10}

\blue{\sf \implies Work \ Done \ (W) = 100 \times m}

According to the Question,

We are asked to find how much water will the pump lift every minute to a height of 10 m with a power 2kW

Therefore,

To Find How much water will the pump lift

Using the Formula,

\orange{\boxed{\boxed{\sf Power(P)=\dfrac{Work \ Done \ (W)}{Time \ (t)}}}}

Given that,

→ Power ( P ) = 2kW = 2000 W

→ Time ( t ) = 1 minute = 60 seconds

And, We found out,

→ Work Done ( W ) = 100 x m

Substituting the above value of Work Done ( W ) in the Power Formula

We get,

\green{\implies \sf 2000=\dfrac{100 \times m}{60}}

\green{\implies \sf 2000 \times 60=100 \times m}

\green{\implies \sf \dfrac{2000 \times 60}{100} =m}

\green{\implies \sf m=\dfrac{2000 \times 60}{100}\;kg}

\green{\implies \sf m=\dfrac{120000}{100}\;kg}

\green{\implies \sf m=1200\;kg}

Hence,

The pump can raise

1200 kg

water per minute up to 10 m height

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