CBSE BOARD X, asked by Dev0000, 1 year ago

An electric refrigerator of power 400 W is allowed to run 10 hrs. per day.
What is the cost of energy to operate it for 30 days at Rs. 4.00 per kWh
?

Answers

Answered by utpal1855

W=PT. P=400w,,,,t=30×10
W=400×30×10
=120000w

for 1w need 4.00
". 120000w need 4×120000
=480000 R.s.

hope this will help you❤️❤️

Dev0000: Bhai apka Ans alag hh aur niche wale ka alag

utpal1855: oooww....divide the ans with 1000 ...cozz its said kilo watt❤️

Dev0000: I which class do you study

Answered by ansh258

Hey bhaiya ,,,,,,,,,

Myself Shreyash Sinha

Class 7

your answer

given ,

power =400 watt

time =10hrs

after 30 days ,

P = 400×30=12000W

t=10×30=300 hrs

energy consumed= P×t

=12000×300

=3600000=3600kWh

Cost of 1kWh= Rs.4

Cost of 3600kWh=Rs.14400

Thank You

ansh258: bhaiya mark me as a brainlest

Dev0000: Bhai apka Ans alag hh aur uper wale ka alag

utpal1855: my ans is the correct one dont worry.......i have many maths like this ..and i solve your one with the help of my teachers note

utpal1855: have done*

Dev0000: In which class do you study

utpal1855: 10....in bangladesh

Dev0000: Okkk

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