Math, asked by anmol4032, 11 months ago

FIND THE ROOTS OF THIS EQUATION ...

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sohil88: 2x*2-x+1/8=0. 16*2-8x+1=0 16*2-4x-4x+1=0. 4x(4x-1)-1(4x-1)=0 ( 4x-1)(4x-1)=0 x=1/4. x=1/4

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Answers

Answered by Ashal

here's your answer

hope this helps

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Ashal: if u ask i ll surely help

anmol4032: ISSI QUESTION ki

Ashal: just completed the square methos

anmol4032: okok I understood

Ashal: method*

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Answered by arjun7774

16x^2-8x+1

=16x^2-4x-4x+1

=4x(4x-1)-1(4x-1)

=(4x-1)(4x-1)

x=1/4, 1/4

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