Physics, asked by chinmay1432p, 11 months ago

An electric refrigerator rated 200w operated in hour/day. What is the cost of the energy to operate it for 30 days at Rs.4.00 per kwh?

Answers

Answered by yamuna041
2

refrigerator =200/1000*1=0.2kwh

total energy in one day=0.2kwh

in 30 days=0.2*30=6

energy to operate it for 30 days at Rs 4.00=6*4.00=24.00

Answered by AakashKumaran
1

Answer:

Given, Power = 200 W

time= 1 hour per day, for 30 days

= 30*1=30 hours

energy= power *time.

= 200*30

= 6000W hour.

but commercial unit of energy is kilowatt hour. so we need to convert our answer into kWh.

= 6000/1000= 6 kWh since 1W= 1/1000KWh

given 4 rs per kWh

thus cost is 4 * 6= 24 rupees

24 rs

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