An electric refrigerator rated 400 W is used for 8 hours a day. An electric iron
box rated 750 W is used for 2 hours a day. Calculate the cost of using these
appliances for 30 days, if the cost of 1 kWh is Rs. 3/-.
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Answered by
1
Answer:
Given,
Power = P = 400W = 400/1000 kW = 0.4 kW
Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h
Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh
Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR.
hope it helps ☺️
Answered by
1
‼hola‼
(1) - refrigerator
power = 400w
time. = 8 hrs
electrical energy = power* time
E. E. = 400/1000*8
= 3.2kwh
(2) - iron box
power = 750w
time. = 2hrs
electrical energy = 750/1000*2
= 1.5kwh
cost of 1kwh = rupees 3
cost of 1.5kwh = 4.5 rs
cost of month = 4.5*30
= 135 rs
hope it helps
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