Physics, asked by gouribiradar1986, 13 days ago

an electric refrigerator rated 400 watt is used for 8 hours a day and electric iron box is rated 750 what is used for 2 hours a day calculate the cost using the appliance for 30 days if the cost of one kilowatt hour is RS 3 rupees​

Answers

Answered by johnjoshua0210
0

Answer:

Power =0.4kW

Energy =0.4/8=0.05J

Cost for 1KWH=Rs.3

Cost for 0.5=0.15rs

For 30 days =4.5Rs

Power =0.75KWH

E=P/T

E=0.750/2=0.375

Cost for 1KWH=Rs.3

Cost for 0.375=Rs.33.75Rs Total Cost t=33.75+4.5=Rs.38.25

Answered by IPSITALONDHE
0

Answer:

Rs.38.25

Explanation:

Power =0.4kW

Energy =0.4/8=0.05J

Cost for 1KWH=Rs.3

Cost for 0.5=0.15rs

For 30 days =4.5Rs

Power =0.75KWH

E=P/T

E=0.750/2=0.375

                                 Cost for 1KWH=Rs.3

                                  Cost for 0.375=Rs.33.75Rs

                                     Total Cost t=33.75+4.5

                                                =Rs.38.25

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