an electric refrigerator rated 400 Watts operate 8 hours a day what is the cost of the energy to operate it for 30 days at 3 rupees per kilowatt hour
Answers
Answered by
7
w=pt
400×8×30
96000watt
= 96 kwh
so cost = 96×3=288rs
400×8×30
96000watt
= 96 kwh
so cost = 96×3=288rs
Answered by
12
Answer:
hey mate here is your answer....
Explanation:
➡️ The total energy consumed by refrigerator in 30 days would be
- 400W x 8.0 hours/day x 30 days = 96000 W h or 96 kW h
▶️ The cost of energy to operate the refrigerator for 30 days is
- 96 kW h x ₹ 3.00 per kW h = 288.00
Hope it helps!✌️
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