An electric refrigerator rated 400W and an electric bulb rated 100W. Operates 10hours/day. What is the cost of the energy to operate it for 10days at Rs 8.00 per kWh?
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Answer:
Given,
Power = P = 400W = 400/1000 kW = 0.4 kW
Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h
Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh
Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR
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