Physics, asked by ojaswik7372, 11 months ago

AN electric refrigerator rated 400W operates 8 hour a day. What is the cost of the energy to operate it for 30 days at₹3.00 per kWh?

Answers

Answered by srimanchintapally
12

Answer:

288 rs

Explanation:

perday 400×8=3200whr

=3.2kwhr=3.2 units

permonth =3.2×30=96 units

cost=96×3=288rs

Answered by dryash1009
1

Answer:

Given: (P) = 750 W

= 750

1000

kW = 75

100

(t) = 2 × 30 = 60 hours

Unit cost = ` 3

To find: Total Cost = ?

Formula: H = P × t

Solution: H = P × t

Explanation:

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