an electric refrigerator rated 450 watt operated 8 hours per day what is the cost of energy to operate it for 40 days at the rupees of 5.00 per kWh
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power =450W
time=8hours
Energy consumed=450*8=3600%1000=3.6
energy consumed=3.6KW
energy consumed in 40 days =3.6*40=144KW
cost=144*5=Rs.720
time=8hours
Energy consumed=450*8=3600%1000=3.6
energy consumed=3.6KW
energy consumed in 40 days =3.6*40=144KW
cost=144*5=Rs.720
Answered by
1
power =450 watt =450/1000 kilowatt
Time = 8 hours
Energy concerved in 1 day = [(450/1000)×8]kWh =3.6kWh
Energy conserved in 40 days =3.6×40 =144kWh
cost of energy =Rs [144×5] =Rs [720]
Time = 8 hours
Energy concerved in 1 day = [(450/1000)×8]kWh =3.6kWh
Energy conserved in 40 days =3.6×40 =144kWh
cost of energy =Rs [144×5] =Rs [720]
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