an electric refrigirator rated 400w operastes 8 hr /day.wt is the cost of energy to operate it for 30 days at rs.3.00 per kwh
Answers
Answered by
5
hello friend!!
here's ur solution :-
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the total energy consumed by the refrigerator in 30 days would be
400W* 8.0 hr/day*30days = 96000 W h
= 96 kW h
thus the cost of energy to operate the refrigirator for 30 days is
96 kW h * Rs.3.00 per kWh =Rs 288.00
========================================================
Hope it helps ya buddy !! :-)
here's ur solution :-
============================================================
the total energy consumed by the refrigerator in 30 days would be
400W* 8.0 hr/day*30days = 96000 W h
= 96 kW h
thus the cost of energy to operate the refrigirator for 30 days is
96 kW h * Rs.3.00 per kWh =Rs 288.00
========================================================
Hope it helps ya buddy !! :-)
LOGOAPPKO:
thax
Answered by
1
Hi !
power = 400 W
time = 8hr
energy consumed in 1 day = power × time
= 400 × 8
= 3200 Wh
= 3.2 kWh
Energy consumed in 30 days = 3.2 × 30 = 96 kWh
==============================================
Rate = Rs 3 / kWh
Total cost = 3 × 96 = Rs 288
power = 400 W
time = 8hr
energy consumed in 1 day = power × time
= 400 × 8
= 3200 Wh
= 3.2 kWh
Energy consumed in 30 days = 3.2 × 30 = 96 kWh
==============================================
Rate = Rs 3 / kWh
Total cost = 3 × 96 = Rs 288
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