Question

An electric room heater has a resistance of 25 ohms and operate at 220v for 12 minutes. Calculate the heat energy dissipated by the heater in kilojoules

Answer 1

Power=v^2/R

220*220/25

=1936watt

1936=heat dissapiated/time in sec

1936=H/12*60

H=1936*12*60=13,93,920J

=1393.920KJ

Hope u understand buddy

Answer 2

Answer:

Explanation:

Power=v^2/R

220*220/25

=1936watt

1936=heat dissapiated/time in sec

1936=H/12*60

H=1936*12*60=13,93,920J

=1393.920KJ