Question

An electric train is moving with a velocity of 120 km/h.How much distance will it cover in 30s?​

Answer 1

Answer:

velocity = 120 km/h x 5/18 = 100/3 m/sec

.

time= 30 sec

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distance= v x t

.

=100/3 x 30

=1000 m

.

so distance or displacement travelled by the

electric train moving with velocity 12Okm/h in 30

sec is 1000 m.

.

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Answer 2

Answer:

$= an \: electric \: train \: is \: moving \: wih \: a \: velocity \: of \: 120 \: kmper \: hour \\ = 1 \: hour \: = 60 \times 60\: = 3600 \: second \\ = 1 \: second \: \: = \frac{120}{3600} \\ = 30 \: seconds \: = \frac{120}{3600} \times 30 \\ = 30 \: second = 1 \: km \\ \\ ⭐1 \: km = 1000m \\⭐ the \: train \: moves \: 1000m \: in \: 30 \: seconds. \\ \\ \\⭐ hope \: it \: helps$