An electric tungsten bulb is connected into home circuit. The home electric supply runs at 220V potential difference. What is the power of bulb (see Q.4 in photo)
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I am sorry
but u don't click photo
but u don't click photo
mondalkartik648:
Solution: P = VI = 220×0.45 P= 99W therefore P= 99÷1000 kW H=P×t = 99÷1000×10 ;H = 0.99kWh
ok
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0.99 potential difference
Given : V - 220V
ok
thanks
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