Question

An electrical appliance having a resistance of 2000 is operated at 200 V. Calculate the energy consumed by the appliance in 5 minutes in
kWh.
Ans. 0.0167kwh​

Answer 1

Explanation:

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Answer 2

R=2000ohm
V=200V
I(current)=V/R
I=200/2200
I=1/11
Energy= V*I*time(in hour)/1000
Energy=220*1/11*1/12/1000
E=1.67/1000
E=0.0167kWh